--Stay hungry, stay foolish.
--Forever young, forever weep.
https://leetcode.com/problems/sort-characters-by-frequency/description/
Given a string, sort it in decreasing order based on the frequency of characters.
Example 1:
Input:
"tree"
Output:
"eert"
Explanation:
'e' appears twice while 'r' and 't' both appear once.
So 'e' must appear before both 'r' and 't'. Therefore "eetr" is also a valid answer.
Example 2:
Input:
"cccaaa"
Output:
"cccaaa"
Explanation:
Both 'c' and 'a' appear three times, so "aaaccc" is also a valid answer.
Note that "cacaca" is incorrect, as the same characters must be together.
Example 3:
Input:
"Aabb"
Output:
"bbAa"
Explanation:
"bbaA" is also a valid answer, but "Aabb" is incorrect.
Note that 'A' and 'a' are treated as two different characters.
class Solution: def frequencySort(self, s): """ :type s: str :rtype: str """ cs_dict = dict() for c in s: cs_dict[c] = cs_dict.setdefault(c, 0) + 1 cs_list = [(n, c) for c,n in cs_dict.items()] cs_list.sort(reverse=True) return ''.join(c*n for n,c in cs_list)